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AlladinOne [14]
3 years ago
10

During track practice, Jonathan ran 5 kilometers. Rob 4,250 meters. Who ran further?​

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
7 0

Answer:

Johnathan

Step-by-step explanation:

motikmotik3 years ago
4 0

Answer: The answer is: Jonathan ran further.

Step-by-step explanation: First, 1 kilometer (km )= 1,000 meters (m)

Then,multiply 5 times 1,000 because Jonathan ran 5 kilometers and were using meters. (We’re converting. )The answer for that is 5,000 meters. Remember to change kilometers to meters! This is greater than of that of Rob did. ( 4,250 meters. ) So,we know that Jonathan ran further then Rob.

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
den301095 [7]

Answer:

multiply

Step-by-step explanation:

4 0
3 years ago
If f(x)=−5x−8 and g(x)=2x+1, then what is (f∘g)(5.7)?
inna [77]

Answer:

(f*g)(5.7)= -452.6, hopefully that answers your question

7 0
2 years ago
|2n+5|>/9 solve for n?
levacccp [35]
|2n+5|\geq9\iff2n+5\geq9\ or\ 2n+5\leq-9\ \ \ |subtract\ 5\ from\ both\ sides\\\\2n\geq4\ or\ 2n\leq-14\ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{n\geq2\ or\ n\leq-7}\\\\Answer:\boxed{\boxed{n\in(-\infty;-7]\ \cup\ [2;\ \infty)}}
5 0
3 years ago
Read 2 more answers
The areas of two similar rectangles are 192 cm2 and 363 cm2. What is the similarity ratio of the two rectangles?
butalik [34]
A = ab ( the area of rectangle )
a b = 192
a b r² = 363
192 r² = 363
r = √363 / 192 = √121/64
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The similarity ratio of the two rectangles is 11/8.
8 0
3 years ago
Read 2 more answers
) The National Highway Traffic Safety Administration collects data on seat-belt use and publishes results in the document Occupa
asambeis [7]

Answer:

We conclude that there is a difference in seat belt use.

Step-by-step explanation:

We are given that of 1,000 drivers 16-24 years old, 79% said they buckle up, whereas 924 of 1,100 drivers 25-69 years old said they did.

<u><em>Let </em></u>p_1<u><em> = population proportion of drivers 16-24 years old who buckle up .</em></u>

<u><em /></u>p_2<u><em> = population proportion of drivers 25-69 years old who buckle up .</em></u>

So, Null Hypothesis, H_0 : p_1-p_2 = 0      {means that there is no significant difference in seat belt use}

Alternate Hypothesis, H_A : p_1-p_2\neq 0      {means that there is a difference in seat belt use}

The test statistics that would be used here <u>Two-sample z proportion statistics;</u>

                     T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of drivers 16-24 years old who buckle up = 79%

\hat p_2 = sample proportion of drivers 25-69 years old who buckle up = \frac{924}{1100} = 84%

n_1 = sample of 16-24 years old drivers = 1000

n_2 = sample of 25-69 years old drivers = 1100

So, <u><em>test statistics</em></u>  =  \frac{(0.79-0.84)-(0)}{\sqrt{\frac{0.79(1-0.79)}{1000}+\frac{0.84(1-0.84)}{1100} } }  

                              =  -2.946

The value of z test statistics is -2.946.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u><em>Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</em></u><em> </em>

<em>Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that there is a difference in seat belt use.

4 0
3 years ago
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