The gcf of 25 and 14 would be 2
There are 50 different possible debating teams that could be selected as obtained using COMBINATION.
Since there are EQUAL number of juniors and seniors ;
Then we have 5 of each.
Here, the order of arrangement DOES NOT matter, Hence, we use COMBINATION
since the team MUST contain 4 SENIORS and 2 JUNIORS
4 Seniors from 5 = 5C4 = 5
2 Juniors from 5 = 5C2 = 10
Hence, (5C4 * 5C2) = 5 * 10 = 50
Hence, there are 50 different possible debating teams that could be selected.
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Answer:
-7
Step-by-step explanation:
Answer:
-x2+3x-2 so I'm thinking A)
Step-by-step explanation:
1) 5.028 × 10^21
2) 8.46 × 10^22 (ig theres literally nothing else it could be)
3) approx. 17 times greater (rounded up from 16.8)