see attached picture of how graph should look.
search through word for a graph icon, you should be able to do this in Word.
Answer:
6 19/24
Step-by-step explanation:
First, we make the denomanators the same
2 16/24 + 4 3/24
Next, we add
6 19/24
We can't symplify so that's the answer
Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
You get a common denominator. It's 36. Then multiply accordingly to get 16/36-3/36 = 13/36. Hope this helps.
Answer:
y=3x-5
Step-by-step explanation:
parallel means that both lines share the same gradient.
from the equation y=3x-12 , we can deduce that the gradient is 3 because it is in the gradient-intercept form
now substitute values into formula
y-y1=m (x-x1)
y--2=3 (x-1)
expand brackets and simplify
y+2=3x-3
subtract 2 from both sides of equation
y=3x-5
