34.231+45.23 somebody plz help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

A line segment can be drawn between any two points.

Afina-wow [57]

D.

I hope this helped

Please give brainliest :)

4 0

4 years ago

Read 2 more answers

The April precipitation amounts (in inches) for 10 cities are listed below. Find the

musickatia [10]

Answer:

2.75 inches

hope this helps

7 0

3 years ago

Help needed: Solve for x. Round to the nearest tenth, if necessary.

Nookie1986 [14]

Answer:

x = 24.1

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 15°

Adjacent = 90

Opposite = x =?

The value of x can be obtained by using Tan ratio as shown below:

Tan θ = Opposite / Adjacent

Tan 15 = x / 90

Cross multiply

x = 90 × Tan 15

x = 24.1

Therefore, the value of x is 24.1

7 0

3 years ago

locate the point on the line segment A (3,-5) and B (13,-15) given that the point is 4/5 of the way from A to B. Show your work

rjkz [21]

Answer:

The coordinates of the point on the line segment between A (3 , -5) and B (13 , -15) given that the point is 4/5 of the way from A to B would be: (11 , -13)

Step-by-step explanation:

As the line segment has the points:

A(3, -5)

B(13, -15)

Let (x, y) be the point located on the line segment which is 4/5 of the way from A to B.

Using the formula

$x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$

$y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

Here, the point (x , y) divides the line segment having end points (x₁, y₁) and (x₂, y₂) in the ratio m₁ : m₂ from the point (x₁, y₁).

As (x, y) be the point located on the line segment which is 4/5 of the way from A to B, meaning the distance from $A$ to $(x , y)$ is $4$ units, and the

distance from $(x , y)$ to B is 1 unit, as $5 - 4 = 1$ .

Thus

m : n = 4 : 1

so

Finding x-coordinate:

$x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$

$x=\frac{\left(3\right)\left(1\right)+\left(13\right)\left(4\right)}{4+1}$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$x=\frac{3\cdot \:1+13\cdot \:4}{4+1}$

$x=\frac{55}{4+1}$ ∵ $3\cdot \:1+13\cdot \:4=55$

$x=\frac{55}{5}$

$\mathrm{Divide\:the\:numbers:}\:\frac{55}{5}=11$

$x=11$

Finding y-coordinate:

$y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

$y=\frac{\left(-5\right)\left(1\right)+\left(-15\right)\left(4\right)}{4+1}$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$y=\frac{-5\cdot \:\:1-15\cdot \:\:4}{4+1}$

$=\frac{-65}{4+1}$ ∵ $-5\cdot \:1-15\cdot \:4=-65$

$=\frac{-65}{5}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$y=-\frac{65}{5}$

$y=-13$

so

The x-coordinate = 11

The y-coordinate = -13

Therefore, the coordinates of the point on the line segment between A (3 , -5) and B (13 , -15) given that the point is 4/5 of the way from A to B would be: (11 , -13)

7 0

3 years ago

Determine whether the given measures can be the lengths of the sides of a triangle write yes or no

ohaa [14]

NO.,the given measures can not be the lengths of the sides of a triangle

Step-by-step explanation

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

so, Find the range for the measure of the third side of a triangle given the measures of two sides.

here given measures are 2,2,6

2+2 = 4 which is less than the third side 6

= 4 < 6

This not at all a triangle.

Hence, the given measures can not be the lengths of the sides of a triangle

3 0

4 years ago