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Vesna [10]
3 years ago
6

To calculate the hourly revenue from the buffet after x $1 increases, multiply the price paid by each customer and the average n

umber of customers per hour. Create an inequality in standard form that represents the restaurant owner’s desired revenue. Type the correct answer in each box. Use numerals instead of words. x2 + x + ≥
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:

The question is not complete,find below complete question

Noah manages a buffet at a local restaurant. He charges $10 for the buffet. On average, 16 customers choose the buffet as their meal every hour. After surveying several customers, Noah has determined that for every $1 increase in the cost of the buffet, the average number of customers who select the buffet will decrease by 2 per hour. The restaurant owner wants the buffet to maintain a minimum revenue of $130 per hour.

Noah wants to model this situation with an inequality and use the model to help him make the best pricing decisions.

To calculate the hourly revenue from the buffet after x $1 increases, multiply the price paid by each customer and the average number of customers per hour. Create an inequality in standard form that represents the restaurant owner’s desired revenue.

Type the correct answer in each box. Use numerals instead of words. x2 + x + ≥

Price is $8

Step-by-step explanation:

The minimum revenue of $130 is a function price multiplied by number of buffet sold

initially price per buffet was $10

16 buffet sold per hour

when cost of buffet to customer increases by $x,the number of customer would decrease by 2 multiplied x since x is the increase in the price that has turned customers away

(10+x)(16-2x) less than or equals 130

by opening brackets we have

160+16x-20x-2x^2 less than equals 130

if we divide the equation by 2

80+8x-10x-x^2

8(10+x)-x(10+x)

8-x=0 or x+10=0

x=8 0r -10

price cannot be negative hence x is $8

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a. N(500, 100)

Step-by-step explanation:

The normal probability distribution, with mean M and standard deviation S, can be represented in the following notation.

N(M,S).

In this problem, we have that:

Mean = 500

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a. N(500, 100)

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The volume of a cylinder is 441 cubic centimeters and its radius is 7 centimeters.
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A multiple-choice examination has 15 questions, each with five answers, only one of which is correct. Suppose that one of the st
Alex

Answer:

0.0111% probability that he answers at least 10 questions correctly

Step-by-step explanation:

For each question, there are only two outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent from other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct.

This means that n = 15, p = \frac{1}{5} = 0.2

What is the probability that he answers at least 10 questions correctly?

P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{15,10}.(0.2)^{10}.(0.8)^{5} = 0.0001

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P(X = 12) = C_{15,12}.(0.2)^{12}.(0.8)^{3} \cong 0

P(X = 13) = C_{15,13}.(0.2)^{13}.(0.8)^{2} \cong 0

P(X = 14) = C_{15,14}.(0.2)^{14}.(0.8)^{1} \cong 0

P(X = 15) = C_{15,15}.(0.2)^{15}.(0.8)^{0} \cong 0

P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.0001 + 0.000011 = 0.000111

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3 years ago
The graph shows the vertical displacement y, in inches, that a weight bouncing from a spring world achieve if there were no fric
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Option B. \frac{1}{6}

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we know that

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Remember that

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Look at the picture.

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