I really need help on these last four, thank you!!
1 answer:
Answer:
So it looks like you only have two more questions there.
9.433.01 in ^2
10. To be determined...
Step-by-step explanation:
Here we have a bit of the same dilemma as the last problem. We are splitting the diagrams up into small triangles.
But, as before, we still don't have all the variables that are required.
This time, though, we will be making use of a 30-60-90 triangle. Although they are a bit more fiddly than a 45-45-90, they are much more useful.
The pentagon in number 9 is of especial interest. We know that we have a bottom length of 10, so that makes a perimeter of 50 in (5*10)
We also see that the apothem of the pentagon is the only thing remaining in our equation to be found.
To find the apothem:
a==17.32
To find the area of the diagram:
17.32*10=173.20
173.21/2=86.60
86.60*5=433.01 in ^2
Sorry it took me so long.....can you do #10?
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9514 1404 393
Answer:
x = -4/3y² -40/3y -103/3
x = -4/3(y +5)² -1
Step-by-step explanation:
Solve for x.
x = (4y² +40y +103)/(-3)
x = -4/3y² -40/3y -103/3 . . . . 'standard form' in the US
__
Taking our clues from the graph*, we can write the vertex form equation as ...
x = -4/3(y +5)² -1 . . . . . . 'standard form' in other places
_____
* The vertex is (-1, -5), so for some leading coefficient, the equation will be ...
x = a(y -(-5))² +(-1) = a(y +5)² -1
The value of 'a' is the scale factor. Here, that is the difference between the parabola value (x = -2 1/3) and the vertex value (x = -1) one unit away from the vertex.
