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Gnesinka [82]
4 years ago
9

A line rotates in a horizontal plane according to the equation θ = 2t3 - 6t, where θ is the angular position of the rotating lin

e, in radians, and t is the time, in seconds. Determine the angular acceleration when t = 2 sec.
A. 24 radians per sec2
B. 12 radians per sec2
C. 18 radians per sec2
D. 6 radians per sec2
Mathematics
1 answer:
Feliz [49]4 years ago
7 0
The acceleration is the second derivative of \theta.

first derivative: 6t^2-6. Second derivative 2t. For t= 2, we get theta = 24. The correct answer is A, 24 second^2
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Leo bought a TV at a Black Friday sale for $255. The TV was on sale for 40% off. How much was the original price of the TV?
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4 years ago
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
In two or more complete sentences, compare the number of x-intercepts in the graph of f(x)=x2 to the number of x-
nadezda [96]

Answer

f(x) has 1 x intercept at x=0 because there is an x value that exists when y=0. For g(x), by adding 2 to x^{2} it moves the parent function up 2 so there is now no x-intercept.

Step-by-step explanation:

7 0
4 years ago
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