If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.
<h3>What is the z-score?</h3>
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x - μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.
Then the probability that a cat will weigh less than 11 pounds will be
The value of z-score will be
z = (11 – 9) / 2
z = 1
Then the probability will be
P(x < 11) = P(z < 1)
P(x < 11) = 0.84134
Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.
More about the z-score link is given below.
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X = bessie and y = betty
x + y = 1464
y = 2x - 375
x + 2x - 375 = 1464
3x - 375 = 1464
3x = 1464 + 375
3x = 1839
x = 1839/3
x = 613 <== Bessie gave 613 gallons
y = 2x - 375
y = 2(613) - 375
y = 1226 - 375
y = 851 <== Betty gave 851 gallons
The sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) in our case:
s(n)=3(1-4^n)/(1-4)
s(n)=-(1-4^n)
s(n)=(4^n)-1 and s=1023
(4^n)-1=1023
4^n=1024
n ln4=ln1024
n=(ln1024)/(ln4)
n=5
Answer:2/5
Step-by-step explanation:
Answer:
$132
Step-by-step explanation:
First we need to find the total number of woods required. This would be total area of fence divided by area of each wood. Remember to convert inch into feet.
Now we know the total number of planks, we need to find what is the cost of each plank. We know that one wood plank area is 2 sq. ft ( 6*0.33333). Therefore, the cost of each plank is = cost per area(sq.ft) multiply by total area (sq. ft).
cost per plank = 2 * $1.10 =$2.20.
We have total planks = 60 units and we have cost per plank = $2.20.
So, we can find total cost as 60*2.20= $132
