A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.
b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.
c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.
d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.
.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
Answer:
Therefore, we conclute that the map distance between A and C is 35 m.u..
Step-by-step explanation:
We know that the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20 m.u. We calculate the map distance between A and C.
Therefore, we get

Therefore, we conclute that the map distance between A and C is 35 m.u..
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Solution is in attachment ~
Which means she ran 4160 miles long
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