Determine the quadrant adding or subtracting periods -10pi/3+2pi=-4pi/3+2pi=2pi/3
which is the second quadrant because
first quadrant is between 0 and pi/2
second quadrant is between pi/2 and pi
third quadrant is between pi and 3pi/2
fourth is between 3pi/2 and 2pi
now we find the terminal angle since it is the second quadrant we use theta'=pi-theta=pi-2pi/3=pi/3
sin(pi/3)=sqrt(3)/2 sin is positive in the second quadrant
cos(pi/3)=-0.5 cos is negative in the second quadrant
tan(pi/3)=sin(pi/3)/cos(pi/3)=-sqrt(3) tan is negative in the second quadrant
Answer:
c
Step-by-step explanation:
One side: y+4
Second side: y+4+2=y+6
Third side: 2(y+4)-3= 2y+8-3= 2y-5
Perimeter = y+4+y+6+2y-5= 4y+5
Answer: 23
Step-by-step explanation:
Answer:
57
Step-by-step explanation:
-4x-y+4
plug in the numbers for the letters
-4(-14)-3+4
multiply -4(-14)= 56
56-3+4
subtract 3
53+4
add 4
57
