Find the slope of the line that passes through (1, 14) and (4,10),
2 answers:
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56° and 34°
complementary angles sum to 90° thus
3x - 10 + 2x - 10 = 90
5x - 20 = 90
add 20 to both sides of the equation
5x = 90 + 20 = 110
divide both sides by 5
x = = 22
angle 2x - 10 = (2 × 22) - 10 = 44 - 10 = 34° and
angle 3x - 10 = (3 × 22) - 10 = 66 - 10 = 56°