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Vanyuwa [196]
3 years ago
10

Two workers finished a job in 12 days. How long would it take each worker to do the job by himself if one of the workers needs 1

0 more days to finish the job than the other worker?
Mathematics
2 answers:
nata0808 [166]3 years ago
5 0

Answer:

7 days and 17 days

Step-by-step explanation:

We can write an equation to solve this. An equation could be: <u><em>½x + ½y = 12</em></u>.<u><em> x - y = 10</em></u>. Variables that solve this equation are <u><em>x=7</em></u> and <u><em>y=17</em></u>. 7 + 17 = 24÷2 (since there are 2 workers) =12. Also, ½(7) + ½17 = 3.5 + 8.5 = 12. So, we know that the faster worker will take 7 days and the slower worker will take 17 days.

Hope this helps! Plz give me brainliest, it will help me achieve my next rank.

FromTheMoon [43]3 years ago
4 0

Answer:

20 days

Step-by-step explanation:

t = time required by one worker to complete the job alone

(t+8) = time required by the other worker

So:

7.5/ t + 7.5/ (t + 8) = 1

Solve for t.

...

t = 12 days, the first guy working alone

The other worker would finish the job in 20 days.

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