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Likurg_2 [28]
3 years ago
5

Your school is planning a fundraising dinner. The expense for this event must not exceed $2,475.00. The team organizing the even

t has calculated that the cost per adult guest will be $18.00 and the cost per child guest will be $9.00. The venue can hold no more than 150 guests.
a. Write a system of inequalities that represents this situation.
Mathematics
2 answers:
max2010maxim [7]3 years ago
7 0
18 per adult, 9 per child total equals 2,475,00 and the hold of guest is 150
frez [133]3 years ago
6 0
X is the number of adults attending the event
<span>y is the number of children attending the event. </span>

x + y <= 150 is one equation.
<span>18x + 9y <= 2475 is the other equation. </span>

x >= 0 is another equation that is implied because the number of adults can't be less than 0.

<span>y >= 0 is another equation for the same reason as in x >= 0. </span>

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Use the table to write and solve an equation to find the number of
exis [7]

Answer:

c = 11

Step-by-step explanation:

Given

Cars\ Sold:-: 8; 9; 12; c

Required

What value of c makes the mean = 10

Mean is calculated as

Mean = \frac{\sum x}{n}

In this case;

Mean = 10 and n = 4;

So, we have:

10 = \frac{8+ 9 + 12 + c}{4}

10 = \frac{29+ c}{4}

Multiply both sides by 4

10 * 4 = 29 + c

40 = 29 + c

Solve for c

c = 40 - 29

c = 11

4 0
3 years ago
Juan analyzes the amount of radioactive material remaining in a medical waste container over time. He writes the function f(x) =
forsale [732]
I believe this is right

5 0
2 years ago
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let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

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6 0
1 year ago
32.8g of sugar is needed to make 4 cakes. How much sugar is needed for 7 cakes?
allochka39001 [22]

Answer:

57.4g

Step-by-step explanation:

32.8g of sugar is needed to make 4 cakes. How much sugar is needed for 7 cakes?

From the above questions, we know that:

4 cakes = 32.8g

7 cakes = x g

Cross Multiply

4 × xg = 7 × 32.8g

x = 7 × 32.8g/4

x = 57.4 g

Therefore, 57.4g is needed for 7 cakes

6 0
2 years ago
Which of the following is the equation of a line parallel to 3y=6x+5 that passes through (2,3)?
Verdich [7]

Answer:

The answer is C y= 2x-1

Step-by-step explanation:

7 0
3 years ago
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