11
n-30=14-3n
you add 3n to both sides
then you'll have 4n-30=14
you add 30 to 14
4n=44
n=11
Ln(xy) - 2x =0
slope of the tangent line = derivative of the function
[ln(xy)]' = [2x]'
[1/(xy)] [y + xy'] = 2
y + xy' = 2(xy)
xy' = 2xy - y =y(2x-1)
y' = y(2x-1)/x
Now use x = -1 to find y and after to find y'
ln(xy) = 2x
x=-1
ln(-y) =-2
-y = e^-2
y = - e^-2
y' = [-e^-2][2(-1)-1]/(-1) = [e^-2](-2-1)= [e^-2](-3) = - 3e^-2
Answer: option 6. from the list
Answer:
It B since The root is obtained when F(x)=0 and if F(x)=y this means y=0 and when you look art graph the y=0 presented in two points x=-4 and x=2
Answer:
a. 8
b. 248
Step-by-step explanation:
first, find the derivative:
-2x^2 + 32x + 120
= -4x + 32
then, have that equal 0
-4x + 32 = 0
32 = 4x
8 = x
answer a: 8
plug in answer a into the original equation
-2(8)^2 + 32(8) +120
answer b: 248
B. Round the addition problems 400+200