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laila [671]
3 years ago
13

PLEASE ITS NOT THAT HARD

Mathematics
2 answers:
nevsk [136]3 years ago
6 0

Answer:

25.   0.0036    26.    1/64

Step-by-step explanation:

s2008m [1.1K]3 years ago
5 0

Answer:

0.06^2= 0.0036  (1/4)^3= 1/64

Step-by-step explanation:

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(8x² + 3x) - 4x² + x-4
serg [7]

Answer:

4x^2+4x-4

Step-by-step explanation:

8x^2 + 3x - 4x^2 + x - 4

= 8x^2 - 4x^2 + 3x + x - 4

= 4x^2 + 4x - 4

4 0
2 years ago
1) how many significant digits are there in the sum of 45.10 and 102.203?
Sergio039 [100]
Oi  :)

1) There are 3 significant digits
45.10+102.203= 147.303

2)
15 Mi/h  =  22 ft/s

3)
C= 72*m* \frac{3}{4} \\  \\ C= 72*81* \frac{3}{4} \\  \\ C= \frac{17496}{4}  \\  \\ C=4374

4)
There are 4 significant digitis. Leter C 
7 0
3 years ago
ATM stands for Automated Teller Machine.
lakkis [162]
This statement is true.
5 0
3 years ago
What is the quotient (2x^2 + 12x +18 ) divided by (x +3)
katen-ka-za [31]
2(x^2+6x+9) = 2(x+3)^2

So after divided by (x+3), answer will be:

2(x+3)
6 0
3 years ago
to avoid a large shallow reef a ship set a course from point a and traveled 24 miles east to point b . the ship them turn and tr
Sever21 [200]
First, we are going to find the distance traveled by the ship adding the tow distances:
Distance traveled= 24 mi +33 mi=57 mi

Next, we are going to use the Pythagorean theorem to find the distance from a to c:
d^2=24^2+33^2
d^2=576+1089
d^2=1665
d= \sqrt{1665}
d=40.8 mi

Finally, we are going to subtract the two distances:
57 mi -40.8 mi= 16.2 mi

We can conclude that <span>if the ship could have traveled in a straight lime from point a to point c, it could have saved 16.2 miles.</span>

7 0
3 years ago
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