Answer:
12.5%
Step-by-step explanation:
I warn you, I'm not positive I'm correct.
First I added 8+10+6 and got 24
I divided that by 3 and got 8
I divided 100 by 8 because if you cross multiply 1/8 and x/100 you would get 8x = 100
100 ÷ 8 = 12.5
So I got 12.5%
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
85 parking spaces
Step-by-step explanation:
Given that :
Parking spaces on floors :
Let first floor = x
Second floor = 2x
Third floor = 2x + 3
Total parking spaces = 428
THEREFORE ;
x + 2x + 2x + 3 = 428
5x + 3 = 428
5x = 428 - 3
5x = 425
x = 425 / 5
x = 85
Hence, there are 85 parking spaces on the first floor
9514 1404 393
Answer:
(6,2)
Step-by-step explanation:
As is often the case with multiple-choice problems, you don't actually need to know the detailed working. You just need to know what the answer looks like.
When point X is dilated by a factor of 2 with point Z as the center of dilation, it will move to a location twice as far from Z. You can tell by looking at the graph that X' will be in the first quadrant, above and to the right of the location of X. The only sensible answer choice is ...
X' = (6, 2)
_____
<em>Additional comment</em>
X is a distance of X-Z = (4, 0) -(2, -2) = (2, 2) from Z Doubling that will put the image point a distance of 2(2, 2) = (4, 4) from Z. When this is added to Z, we find ...
X' = Z + (4, 4) = (2+4, -2+4) = (6, 2)
Answer:
its D
Step-by-step explanation:
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180-65
