A.3n+4+3n+4+4n
=3n+3n+4n+4+4
=10n+8
B.11n+4+n-12
=11n+n+4-12
=12n-8
C.6(6n-2)
=36n-12
D.4(3n-2)
=12n-8
E.4n+22-12+8n
=4n+8n+22-12
=12n+10
so,B and D are the expressions that are equivalent to 12n-8.
Answer: 28
Step-by-step explanation:
Simplifying
2x + 16 = 3x + -12
Reorder the terms:
16 + 2x = 3x + -12
Reorder the terms:
16 + 2x = -12 + 3x
Solving
16 + 2x = -12 + 3x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-3x' to each side of the equation.
16 + 2x + -3x = -12 + 3x + -3x
Combine like terms: 2x + -3x = -1x
16 + -1x = -12 + 3x + -3x
Combine like terms: 3x + -3x = 0
16 + -1x = -12 + 0
16 + -1x = -12
Add '-16' to each side of the equation.
16 + -16 + -1x = -12 + -16
Combine like terms: 16 + -16 = 0
0 + -1x = -12 + -16
-1x = -12 + -16
Combine like terms: -12 + -16 = -28
-1x = -28
Divide each side by '-1'.
x = 28
Simplifying
x = 28
<h2><em><u>Answ</u></em><em><u>er</u></em><em><u>:</u></em><em><u>-</u></em></h2>
★ Input of the given function F(x) is 5.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
<h3>• <u>Given</u><u>:</u><u>-</u></h3>
✯ F(x) = 7x - 9
✯ Output = 26
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
<h3>• <u>Solution</u><u>:</u><u>-</u></h3>
According to the question the output is 26.
Hence, the above data can be written in an equation form.
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
➪ F(x) = 7x - 9 = 26
➪ 7x = 26 + 9
➪ 7x = 35
➪ 
➪ 
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
Therefore, F(x) = 5
Answer:
Step-by-step explanation:
8. 







9. 


10. 


11. 6.9 < x - 2.3
+ 2.3 + 2.3
9.2 < x = x > 9.2
Hope this helps!
Answer:
A. the error term has a constant variance
Step-by-step explanation:
Firstly, note that it is observed the residuals increase as the predicted value increases. Now the natural logarithm transformation will change will change a skewed variable into a normal distributed value, which leads to a linear regression between the both variables, since they (the independent and dependent variables) are normal. A key assumption of linear regression is Homoscedasticity, therefore the error term obtains the same finite variance.
So as soon as the transformation is applied, the error term will therefore have a constant variance.