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WITCHER [35]
3 years ago
15

Work out the percentage change to 2 decimal places when a price of £99 is increased to £111.

Mathematics
1 answer:
Basile [38]3 years ago
6 0

Answer:

0.12

Step-by-step explanation:

The percentage change formula depends if the price goes up or down. Since this goes up, we have the positive percentage change formula. This is \frac{ a_n - a_1}{a_1} where a_n is the new price and a_1 is the original price. Plugging in our values, we get \frac{111-99}{99} = \frac{12}{99}  = 0.\overline{12} . Since this is to two decimal places we get 0.12 as our answer.

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Leona [35]
He’s correct good job!
7 0
3 years ago
S+f=24 s=3f<br><br> I need this now
scoundrel [369]

Answer:

f=6 and s=18

Step-by-step explanation:

Let's solve your system by substitution.

s+f=24;s=3f

Rewrite equations:

s=3f;f+s=24

Step: Solves=3ffor s:

s=3f

Step: Substitute3fforsinf+s=24:

f+s=24

f+3f=24

4f=24(Simplify both sides of the equation)

4f

4

=

24

4

(Divide both sides by 4)

f=6

Step: Substitute6forfins=3f:

s=3f

s=(3)(6)

s=18(Simplify both sides of the equation)

Answer:

f=6 and s=18

4 0
3 years ago
Find the distance between (-5,-6) and (-3,-8 WILL GIVEBRANLIEST TO FIRST PERSON WHO AWNSES WITH EXPLANATION
Vlada [557]

Answer:

d = √8

d ≈ 2.82843

Step-by-step explanation:

Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Simply plug in our coordinates into the distance formula:

d = \sqrt{(-3 + 5)^2+(-8 + 6)^2}

d = \sqrt{(2)^2+(-2)^2}

d = \sqrt{4+4}

d = \sqrt{8}

To find the decimal, simply evaluate the square root:

√8 = 2.82843

8 0
3 years ago
Read 2 more answers
Can someone help me with this please :,)
wolverine [178]

Answer: 43.07

Step-by-step explanation:

3 0
2 years ago
After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum
Svetlanka [38]

Answer:  40000

Step-by-step explanation:

The formula to find the sample size is given by :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2, where p is the prior estimate of the population proportion.

Here we can see that the sample size is inversely proportion withe square of margin of error.

i.e. n\ \alpha\ \dfrac{1}{E^2}

By the equation inverse variation, we have

n_1E_1^2=n_2E_2^2

Given : E_1=0.05   n_1=1000

E_2=0.025

Then, we have

(1000)(0.05)^2=n_2(0.025)^2\\\\\Rightarrow\ 2.5=0.000625n_2\\\\\Rightarrow\ n_2=\dfrac{2.5}{0.000625}=4000

Hence, the sample size will now have to be 4000.

6 0
2 years ago
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