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tiny-mole [99]
3 years ago
5

Multiply 37 by 3 now multiply 37 by 6 what would you have to multiply 37 by to get all fives

Mathematics
2 answers:
Vlad [161]3 years ago
4 0
37 x 15 = 555 would be it
alisha [4.7K]3 years ago
3 0
You would have to multiply 37 by 15
37 x 15 = 555
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Step-by-step explanation:

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I'll use arithmetic series to find it.

First two-digit number divisible by 3 is 12, last such number is 99. Every 3rd number is divisible by 3.

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a_1=12\\a_n=99\\d=3\\n=?\\\\a_n=a_1+(n-1)\cdot d\\99=12+(n-1)\cdot 3\\3n-3=87\\3n=90\\n=30

<u>There are 30 such numbers.</u>

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