Answer:
1.794
Step-by-step explanation:
use the calculator
Answer:
"simplify" it
Step-by-step explanation:
To convert from vertex form to standard form for a quadratic, eliminate parentheses and collect terms. In short, "simplify" it.
Answer:
C, f(x) = 2x + 6
Step-by-step explanation:
First, we need to plug in the values of the x coordinates and see if it matches with the y coordinate to determine if it is on the same line. Startin with 2x + 8, we have the point (1, 8) on the graph. Plugging in 1 gets you 10 for the y. This is wrong since 8 is the y coordinate. Moving on, we have 6.4(1.25)^x for the same point. Plugging in 1, we have 6.4 * 1.25 = 8, which is true. Moving on to the second point, (2, 10), we have 1.25 squared times 6.4. This is thus wrong. So, moving on to 2x + 6, we have the point (1, 8), and plugging in 1 for x, we have 8 as y. Since this satisfies the equation we move on to the next point, (2,10). Plugging in x, we have 2 * 2 + 6 = 10, which is also true. Moving on to our third point (3 , 12), we plug in 3 for x. We then get 3 * 2 + 6 = 12, which is correct. This, is our answer then.
A) T(m) = -0.16m +331.3
B) T(2015) = 8.9 . . . seconds
_____
The linear regression function of a graphing calculator can find the equation of the line easily. Or, you can use the 2-point form of the equation of a line.
.. T(m) = (10.5 -14.5)/(2005 -1980)*(m -1980) +14.5
.. T(m) = -0.16(m -1980) +14.5
Answer:
<em>Option A; the tournament did begin with 128 teams</em>
Step-by-step explanation:
We can see that this equation is represented by compound interest, in other words an exponential function, either being exponential growth or exponential decay;
f ( x ) = a + ( b )^x, where a ⇒ start value, b ⇒ constant, x ⇒ ( almost always considered ) time, but in this case rounds
Option A; The equation is given to be t ( x ) = 128 * ( 1/2 )^x. Given by the above, 128 should represent the start value, hinting that the tournament <em>did indeed begin with 128 teams</em>
Option B; As the rounds increase the number of teams approach 128. Now mind you 128 is the start value, not the end value, which would mean that <em>this statement is false</em>
Option C; The tournament began with 1/2 teams. Theoretically that would not be possible, but besides that the tournament began with 128 teams, only differed by 1/2 times as much every round. <em>This statement is thus false</em>
Option D; This situation actually represents exponential decay. If each round the number of teams differed by 1/2 times as much, the number of teams remaining is less than before, and thus this models exponential decay, not growth<em> ( statement is false )</em>
<em>Answer : Option A; the tournament did begin with 128 teams</em>
