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Harman [31]
3 years ago
6

Isaac has spent $20 to set up cable service and the monthly fee is $54.95. Write an equation to represent the total amount it co

sts, C(t) to have cable service if t stands for the number of months the service has been used.
Use functional notation and use only numbers, variables, and mathematical symbols. Using any additional symbols, such as $, will cause auto grade to mark your answer wrong.
Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0
Do 54.95 + 20.00 and you get 80.95
Tanzania [10]3 years ago
6 0
C(t)=54.95(t)+20. 20 dollars is your fixed rate. It will never change. The rest of the function is 54.95 dollars a month multiplied by t months depending on how long he uses cable.
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Answer:

x = tex]5\frac{\textup{7}}{\textup{8}}\ in[/tex]

Step-by-step explanation:

Given:

Total height of the bench = 18 in

Depth of the stone bench = 3\frac{\textup{3}}{\textup{8}}\ in = \frac{\textup{27}}{\textup{8}}\ in  = 3.375 in

Measure of stones = 3\frac{\textup{1}}{\textup{2}}\ in = \frac{\textup{7}}{\textup{2}}\ in  = 3.5 in

measure of another stone =  5\frac{\textup{1}}{\textup{4}}\ in = \frac{\textup{21}}{\textup{4}}\ in  = 5.25 in

let the height of the third stone be 'x'

Now,

The total height of the bench = depth of bench + Measure of two stones + x

18 = 3.375 + 3.5 + 5.25 + x

or

x = 18 - 12.125

or

x = 5.875 in

or

x = tex]5\frac{\textup{7}}{\textup{8}}\ in[/tex]

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2 years ago
Plot and label all the points that are 4 units from point P AND that share the same x coordinate as point P. Write the coordinat
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The answers should be: (-2,5), (-2,-2), (-6,-1), (2,1)





Hope this helped :)
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2 years ago
When is a sum of a geometric sequence finit and when is it infinite?
Olin [163]
Hopefully this will help you

3 0
3 years ago
I get paid $40 a month. If i want 5 less each month, how much should i get paid every week?
agasfer [191]

Answer:

$5 each week

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Trigonometry
quester [9]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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