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3 years ago

Determine and state the coordinates of the center and length of the radius of a circle whose equation is

Mathematics

1 answer:

padilas [110]3 years ago

4 0

First, rewrite the equation in standard form.
The center-radius form of the circle equation is in the format:
(x – h)^2 + (y – k)^2 = r^2
with the center being at the point (h, k) and the radius being "r".

(x-3)^2 + (y+4)^2 = 81

From here, you can determine the center and radius. The center is at (3,-4) and the radius is 9.

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Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

In a math class with 21 students, a test was given the same day that an assignment was due. There were 12 students who passed th

snow_lady [41]

Answer:

5/9

Step-by-step explanation:

The given is students that failed the test. 5 students completed the homework and failed the test and there is a total of 9 students who failed the test. So, the answer would be 5/9

4 0

3 years ago

Find the slope of the line from two points (9, 6) (13,11) Use the equation of the line

mafiozo [28]

Answer:

Step-by-step explanation:

4 0

2 years ago

Evaluate 3x/10 if x= 180

hram777 [196]

Replace x with 180:

3(180)/10 =

540/10 =

Answer : 54

8 0

3 years ago

Read 2 more answers

What is the output of a function when the input is 10?

Blizzard [7]

You did not give us the function

5 0

3 years ago