Determine and state the coordinates of the center and length of the radius of a circle whose equation is
1 answer:
First, rewrite the equation in standard form.
The center-radius form of the circle equation<span> is in the format:
(x – h)^</span>2<span> + (y – k)^</span>2<span> = r^</span>2
<span>with the center being at the </span>point<span> (h, k) and the radius being "r".
</span>
(x-3)^2 + (y+4)^2 = 81
From here, you can determine the center and radius. The center is at (3,-4) and the radius is 9.
The center-radius form of the circle equation<span> is in the format:
(x – h)^</span>2<span> + (y – k)^</span>2<span> = r^</span>2
<span>with the center being at the </span>point<span> (h, k) and the radius being "r".
</span>
(x-3)^2 + (y+4)^2 = 81
From here, you can determine the center and radius. The center is at (3,-4) and the radius is 9.
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Firstly, expand the equation.
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Next, move the variable x to the left and all the constant to the right.
Then, solve for x.