We need explaining and examples not just the question
Equation A find “m” and “b”:
“B” is the y-intercept when x = 0. They give this in the table as “-2” so b = -2
Find slope (m) = (-8)-(-2)/(-2)-0 = 3
Equation A is y = 3x - 2 (y = mx + b)
Equation B find “m” and “b”:
Find m = (-9)-(-5)/(-3)-(-1) = 2
To find be, plug in m, x, and y from ANY coordinates in table b into y = mx + b:
-9 = 2(-3) + b
-9 = -6 + b
b = -3
Equation b is y = 2x -3
Use substitution and substitute all of equation “b” for “y” in equation a:
2x - 3 = 3x - 2
Algebra: x = -1
Plug back into equation a:
y = 3(-1) -2
y = -5
x = -1
(-1, -5) final answer (B)
First, subtract 7 on both sides. Now, you have 4x<1. Divide by 4 on both sides. Finally, you get x<1/4 (a quarter or said as one-fourth). So, x<1/4.
Then the other one is x + 138 - 138 = x So the other one is x
Answer:
y + x + 3
Step-by-step explanation:
each point adds an additional 3
