Part A you can figure out that the car is traveling at 50 miles an hour because after every hour the distance decreases by 50
b the average change is 100 miles for every 2 hours, which can be simplified back to 50mph which represents the speed of the car
part C {y=-50x+900| (0,900),...(18,0)
For this case we must calculate the values of the unknowns.
We have then:

is 3,000 times greater than

We have the following equation:

From here, we clear the value of x:

Then, on the other hand we have:
"and is _____ times greater than 1.38 × 101"
That is, we have the following equation:

The value of y is:
Answer:
6.9 × 105 is 3,000 times greater than 2.3 × 102 and is 50000 times greater than 1.38 × 101.
Answer:
Part A: See detail below.
Part B: Company B charges less than company A for 8 windows.
Part C: The saving using company B for 6 windows is $3.
Step-by-step explanation:
Part A:
Company A: (total charges) = ($6)x(N number of windows)+($12)
Company B: (total charges) = ($5)x(N number of windows)+($15)
Part B:
Company A for 8 windows: 6*8+12=$60
Company B for 8 windows: 5*8+15=$55
Part C:
(Saving) = (6*6+12)-(6*5+15)=48-45= $3
Step-by-step explanation:
let us assume the amount of battery boxes as 3x and pen boxes as 4x
since the battery sale is 4 times more,
3 (4x) =12 x
so 4x +12x = 16x
total money received is 976 rupees
so 16x =976
x =976÷16 = 61
AMOUNT OF BATTERY BOXES =4X = 4×61= 244 BOXES
AMOUNT OF PEN BOXES = X= 61 BOXES