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adoni [48]
3 years ago
11

Find the x-values (if any) at which f is not continuous. which of the discontinuities are removable? (use k as an arbitrary inte

ger. if an answer does not exist, enter dne.) f(x) = csc 5x
Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Here we are to find the values of x in which the function f (x) = csc 5x is discontinuous. What this usually means is to find when the value approaches infinity.

 

We know from trigonometric identities that csc is the equivalent to 1 / sin, therefore the function in terms of sin is:

f(x) = 1 / sin 5x

 

We can see that the function becomes discontinuous when sin 5x = 0, that is a value divided by 0 is discontinuous or approaches infinity.

 

sin 5x is equal to zero when:

5x = 0 or π

So given k as an arbitrary integer

5x = k π

So k can be: k = 0, 1, 2

x = k π/ 5 

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6.32 divided by 54.21
slavikrds [6]
6.32 / 54.21=0.1165



Welcome
7 0
3 years ago
Read 2 more answers
the equation 4(x+9)=76 models this situation which choice shows the sequence of operations neede to slove this problem using bot
laiz [17]

Answer:

Step-by-step explanation:

Here you go mate

Use PEMDAS

Parenthesis,Exponent,Multiplication,Division,Addition,Subtraction

Step 1

4(x+9)=76  Equation/Question

Step 2

4(x+9)=76  Remove parenthesis by multiplying 4

4x+36=76

Step 3

4x+36=76  Subtract 36 from sides

4x=40

Step 4

4x=40  Divide sides by 4

answer

x=10

Hope this helps

5 0
3 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
W=zr-2zt^3 solve for z
ladessa [460]

Answer: z=0

Step-by-step explanation:

W=zr-2zt^3

Move all terms containing z to the left, all other terms to the right.

dd '-1rz' to each side of the equation.

-1rz+z=rz+-1rz+-2t^3z

Combine like terms: rz + -1rz = 0

-1rz+z=0+(-2t^3z)

-1rz+z=-2t^3z

Add 2t^3z to each side

-1rz+2t^3z+z=-2t^3z+2t^3z

Combine the like terms 2t^3z+2t^3z=0

-1rz+2t^3z+z=0

Factor out the Greatest Common Factor (GCF), 'z'.

z(-1r+2t^3+1)=0

Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

8 0
3 years ago
What is 37.06 on ft to sq yrds
Anastaziya [24]
37.06 to yards is 

4.1177 Square yards

5 0
3 years ago
Read 2 more answers
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