The area enclosed is (2x)(600-2x).(2x)(600−2x)=1200x−4x2
In order to maximize we need the derivative to be equal to 0.y′=1200−8x=0
1200=8x
x=150
Therefore the sides for maximum area are 150*300.
<span>The area is: 45000</span>
X=50 because 16 × 156.25 is 2500, then decided by 50 is 50
The answer is 6
i just did the work
