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3 years ago

What is 5 minus 4??? ik its getting harder but im very stuck

Mathematics

2 answers:

mylen [45]3 years ago

7 0

Answer:

5-4=1

Step-by-step explanation:

it would equal 1 since 4+1=5

AleksAgata [21]3 years ago

5 0

Answer:

YoUr AnSwEr Is EqUaL tO oNe

Step-by-step explanation:

5 MiNuS 4 eQuALs 1

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A rhombus has its diagonals 7cm and 6 cm whats its area

ipn [44]

$\large\frak{ Given :}$

Diagonal of a rhombus = 7 cm and 6 cm

$\large\frak{Find:}$

Area of a rhombus

$\large\frak{Explanation :}$

$\small\tt Area = \frac{1}{2}× d¹ × d²$

<u>Where,</u>

d¹ = length of diagonal 1
d² = length of diagonal 2

$\implies \small\tt{ \frac{1}{2} \times 7 \times 6}$

$\implies\small\tt{ \frac{1}{2} \times 42 }$

$\implies \small\tt{Area = 21 {cm}^{2} }$

5 0

2 years ago

the volume of metal in a scale model of a metal high tension tower is 54 cm cubed. The scale used was 1:50. it required 50 mm of

daser333 [38]

Answer:

6,750,000 cm³ = 6.75 m³

Step-by-step explanation:

a scale version means that the ratio of every dimension of scale vs. real object is 1/50.

volume is created by multiplying 3 dimensions.

so, going from scaling to real the volume has to be multiplied by 50×50×50 = 50³ = 125000

so, as for the scale model we needed 54 cm³, for the full size object we need 54×125000 = 6,750,000 cm³ of metal.

or to bring it to m³ (1m³ = 100×100×100 cm = 1000000 cm³)

that would be 6.75 m³ of metal.

3 0

3 years ago

Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from

Lapatulllka [165]

<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$ </h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

$x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and y_3=8$

The area of a triangle is= $\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]$

= $|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|$

= $|-54|$ = 54 square units

The length of AC = $\sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}$

= $\sqrt{(2-12)^{2} +(1-8)^2}$

= $\sqrt{149}$ units

Let the perpendicular distance from B to AC be = x

According To Problem

$\frac{1}{2} \times x \times \sqrt{149} = 54$

⇔ $x =\frac{108}{\sqrt{149} }$ units

Therefore the perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$

5 0

3 years ago

Find all missing angles<br> I need help please

aksik [14]

Answer:

1) 34º

2) 52º

3) 56º

4) 94º

Step-by-step explanation:

let 3 be x

let 1 be y

let 2 be z

let 4 be j

180=86+38+x 56=x

90=56+y 34=y

180=86+j 94=j

180=34+z+94 52=z

4 0

2 years ago

5/5/5/5/5/5/5/55/5/5//5/5/5/5//5/5/5/5/5/5/5/5

AveGali [126]

Answer:

?????????????????????????????????????????????????????????????????????/

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers