The probability that a single radar set will detect an enemy plane is 0.9. if we have five radar sets, what is the probability that exactly four sets will detect the plane?
Solution: The given random experiment follows binomial distribution with 
Let x be the number of radar sets that will detect the plane.
We have to find 


Therefore, the probability that exactly four sets will detect the plane is 0.3281
Answer:
-25
Step-by-step explanation:
when b = 6
sub b = 6 into b^2-9b-7
6^2-9(6)-7
36-54-7
36-61
-25
I know point a=1 But the others not sure
So the equaiton is
number of nickes=n
number of quarters=q
if you have 1 quarter then you have 25 cents so we will represent like this
25q
and nickles is 5n
14.50=1450 cents
so
25q+5n=1480
q+n=88
subtract q from both sides
n=88-q
subsitute into first equation
25q+5(88-q)=1480
25q+440-5q=1480
add like terms
20q+440=1480
subtract 440 from both sides
20q=1040
divide both sdies by 20
q=52
there were 52 quarters
25(52)+5n=1480
1300+5n=1480
subtract 1300 from both sides
5n=180
divide both sides by 5
n=36
there were 36 nickels
nickles=36
quarters=52