Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or, 
or, 
or, 
or, 
Substituting the value of in ∠QPR we get,
∠QPR = 
or, ∠QPR = 
Hence,
The value of ∠QPR is 40°.
Answer:
m = - 5/4
Step-by-step explanation:
If two lines are perpendicular, their slopes are negative reciprocals, which means that their product is -1
We can write the equation
4*x - 5*y + 13 = 0
as: 5*y = 4*x + 13 or
y = (4/5)*x + 13 (1)
Equation (1) is the equation of a straight line in its slope point form, 4/5 is the slope, according to this the slope of a perpendicular line is
-5/4
Answer:
The unknown number is -5.
Step-by-step explanation:
-3 + -5 = -8
-8 - -3 = -5
-8 - -5 = -3
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