Answer:
Total number of ways will be 209
Step-by-step explanation:
There are 6 boys and 4 girls in a group and 4 children are to be selected.
We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.
So the groups can be arranged as
(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)
Now we will find the combinations in which these arrangements can be done.
1 Boy and 3 girls = 
=24
2 Boy and 2 girls=
3 Boys and 1 girl = 
4 Boys = 
Now total number of ways = 24 + 90 + 80 + 15 = 209
Step-by-step explanation:
OP=11.2
m<Q= 42⁰
m<R=48⁰
The tools used are....
I have used the property of Pythagoras Theorm to get the length of side QP, I have also used the property of inverse function of sin to get the measure of angle Q and the property of sum of angles of triangle to get measure of angle of R
Answer:
The answer to your question is He must get 80%
Step-by-step explanation:
Data
Scores 55%, 78%, 84%, 93% and X
Average 80%
Process
1.- Write a equation to solve this problem
- There are five scores
Score 1 = S1 = 55
Score 2 = S2 = 78
Score 3 = S3 = 84
Score 4 = S4 = 93
Score 5 = S5 = X
Equation
Average = (S1 + S2 + S3 + S4 + S5) / 5
- Solve for S5
5 Average = S1 + S2 + S3 + S4 + S5
S5 = 5 Average - S1 - S2 - S3 - S4
- Substitution
S5 = 5(80) - 55 - 78 - 84 - 93
- Simplification
S5 = 400 - 310
- Result
S5 = 90
I'ts 5x, 5x and then x = 1 is 2 and then y = e equals 3 and then 2x + 3 = 5x
