Equation 1. N+D=500
equation 2 5N+10D=3000
This is for equation 1
N=500-d
Substitute into equations 2 and solve for D
5N+10D=3000
5(500-D)+10D=3000
2500-5D+10D=3000
5D=500
D=100
Lets go back the equation 1
N=500-D
N=500-100
N=400
there are 400 Nickles and 100 Dimes
The formula for the area of a triangle of base b and altitude h is A = (1/2)(b)(h).
Here, b = 18 cm and h = 9 cm. Thus, the desired area is:
(18 cm)(9 cm)
A = ----------------------- = 81 cm^2
2
This problem gives you more info than is needed to solve it. The area of the given triangle is 81 cm^2.
Answer:
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Inequality :
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
The following is as far as I get:
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
(n−1)a−(⌊n÷m⌋×(a−b))≥x−α1
n−1−(⌊n÷m⌋×(a−b))≥x−α1a
n−(⌊n÷m⌋×(a−b))≥x−α1a + 1
Step-by-step explanation:
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