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Zigmanuir [339]
3 years ago
13

If the cube has a side length of 10 centimeters, what is the surface area of the cube?

Mathematics
2 answers:
Citrus2011 [14]3 years ago
8 0

Step-by-step explanation:

  • surface area of cube =6a²
  • 6×10²
  • 6×100
  • 600cm²

<h3>stay safe healthy and happy.</h3>
asambeis [7]3 years ago
5 0

Answer:

A=600cm²

Step-by-step explanation:

Solution

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Mario surveyed the 17 healthiest patients in the hospital.
ser-zykov [4K]

Step-by-step explanation:

3 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
What is the justification for step 2 in the solution process?
Maksim231197 [3]

Answer:

Subtract property of deviation becasue your subtracting 6y frrom both sides of the equation.

Step-by-step explanation:

1)Given: 12y - 40 - 4y = 6y - 18

2)Simplify by adding 12y + (-4y): 8y - 40 = 6y - 18

3)Subtract property of deviation: 8y -6y - 40 = 6y -6y - 18

2y - 40 = -18

<em>Hope this helped!</em>

8 0
3 years ago
Read 2 more answers
The midpoint of AB is M(1,−3). If the coordinates of A are (-6, -7) what are the coordinates of B?
abruzzese [7]

Answer:5464

Step-by-step explanation:

6 0
3 years ago
List the integers that satisfy both these inequalities.<br> Put the answers on one line.
bekas [8.4K]

Answer:

-7, -6, -5, -4, -3

Step-by-step explanation:

Given:

2x + 5 < 0

x > -8

Thus, we can combine both statements to find out integers that satisfy both inequalities.

2x + 5 < 0

Let's find x

2x < 0 - 5 (substraction property)

2x < -5

Divide both sides by 2

x < -5/2

This implies that -5/2 is greater than the set of values of x.

The second inequality, x > -8 implies that -8 is less than the value of x.

Les combine both:

-8 < x < -5/2

Therefore, the possible set of integers are whole numbers between the range of -8 and -5/2 which excludes -8 and -5/2.

Thus, they are:

-7, -6, -5, -4, -3

6 0
3 years ago
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