All categories

3 years ago

4 3/2 - 3 1/4 ________

Mathematics

2 answers:

Anarel [89]3 years ago

8 0

4 3/2-3 1/4
11/2-13/4
(22-13)/4
9/4
2 1/4

Taya2010 [7]3 years ago

3 0

3 1
4 --- - 3 ---
2 4

11 13
--- - ---- Common denominator is 4
2 4 Multiply first fraction by 2
(2) (1)

22 13
--- - ---
4 4

9
---
4

1
2 ---
4

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Give me the best answer

Nadya [2.5K]

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3 years ago

Pls halp is the function even, odd, or neither and why

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3 years ago

Read 2 more answers

IF U UNDERSTAND THIS PLS ANSWER WITH NO LINK!!!

Nikitich [7]

Answer:

First Column top:

5. 3. 10

Second Column middle:

9. 7. 2

Third Column bottom:

4. 8. 6

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3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

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3 years ago

A 60 kg dog requires fluids at 50 mL/kg over 24 hours. Using a 10 gtt/mL set how many gtts/min will you set?

Ann [662]

$50\times 10 = 500$
$60 \times 24 = 1400 \: mins$
500/1400= .36gtts per min

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3 years ago