does anyone have all the answers to the 8th grade math DRC interim for vermillion parish. bc I'm here stuck pls help. session 1
2 answers:
Answer:
I think I might have them from last year?
Step-by-step explanation:
You can download answer here
is.gd/qKzpBU
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5 * 6 = 30
90/3 = 30
5 * 6 = 90/3 = 30
![\displaystylef(x)=\int_{0}^{x^2}\sec^2(\sqrt{x})dx \\=\int_{0}^{\sqrt{x^2}}\sec^2(u)\cdot2udu \\=2\int_{0}^{\sqrt{x^2}}\sec^2(u)du \\=2\Big[u\tan(u)-\int\tan(u)du\Big]_{0}^{\sqrt{x^2}} \\=2\Big[u\tan(u)+\ln\Big(\mathrm{abs}(\cos(u))\Big)\Big]_0^x \\=2\Big(x\tan(x)+\dfrac{1}{2}\ln\Big(\cos^2(x)\Big)\Big) \\=2x\tan(x)+\ln(\cos^2(x))](https://tex.z-dn.net/?f=%3C%2Fp%3E%3Cp%3E%5Cdisplaystyle%3C%2Fp%3E%3Cp%3Ef%28x%29%3D%5Cint_%7B0%7D%5E%7Bx%5E2%7D%5Csec%5E2%28%5Csqrt%7Bx%7D%29dx%20%5C%5C%3C%2Fp%3E%3Cp%3E%3D%5Cint_%7B0%7D%5E%7B%5Csqrt%7Bx%5E2%7D%7D%5Csec%5E2%28u%29%5Ccdot2udu%20%5C%5C%3C%2Fp%3E%3Cp%3E%3D2%5Cint_%7B0%7D%5E%7B%5Csqrt%7Bx%5E2%7D%7D%5Csec%5E2%28u%29du%20%5C%5C%3C%2Fp%3E%3Cp%3E%3D2%5CBig%5Bu%5Ctan%28u%29-%5Cint%5Ctan%28u%29du%5CBig%5D_%7B0%7D%5E%7B%5Csqrt%7Bx%5E2%7D%7D%20%5C%5C%3C%2Fp%3E%3Cp%3E%3D2%5CBig%5Bu%5Ctan%28u%29%2B%5Cln%5CBig%28%5Cmathrm%7Babs%7D%28%5Ccos%28u%29%29%5CBig%29%5CBig%5D_0%5Ex%20%5C%5C%3C%2Fp%3E%3Cp%3E%3D2%5CBig%28x%5Ctan%28x%29%2B%5Cdfrac%7B1%7D%7B2%7D%5Cln%5CBig%28%5Ccos%5E2%28x%29%5CBig%29%5CBig%29%20%5C%5C%3C%2Fp%3E%3Cp%3E%3D2x%5Ctan%28x%29%2B%5Cln%28%5Ccos%5E2%28x%29%29%3C%2Fp%3E%3Cp%3E)
Hope this helps.
Answer:
6
Step-by-step explanation:
267. 95cm^3
hope this helped
I think that the answer is 120 cubes
