To find the amplitude and period you need to be familiar with the following equation. Also you need to know that the standard cos has a period of

and the midline is a line that runs between the max and min of the y-values of the function.
Equations:f(x) = A cos(Bx +C) + D
f(x) = -4 cos(2x -n) + 3
A = amplitude = |-4| = 4
B = 2
C = phase shift = n = 0
D = vertical shift = midline = 3
Amplitude = 4
Find the period:
Find the midline:We know that the amplitude is 4 so we have a range from -4 to 4. The standard y = cos(x) has its midline at 0 so y = 0. This is also true for y = -4 cos(x). In your equation though, you have a vertical shift of +3 so this changes our midline. With an amplitude of 4, which gives us a range from -4 to 4(our y-values), the shift moves this up by 3 so that means we will have new
y-values and a range of -1 to 7. Now we need to find the midline(
the middle of our y-values) of our new range. We can find this by using the following formula
Midline:y = 3
Note, in the following equations that D = 3 = midliney = A (Bx+C) + D
y = -4 (2x + n) + 3
Also, the picture that is attached is what your equation looks like when graphed.
Hai
<span>Sally has 2 cups of flour .she uses 3/4 cup to bake muffins and 3/8 cup flour to bake cookies and 3/8 cup flour for pancakes .how much flour does Sally have left?
</span>
1/2
Answer:
The answer is Graph A.
Step-by-step explanation:
Khan academy
Divide 10 by -3 which equals -3.333 repeating
A complete load of concrete = 8 parts gravel + 7 parts water + 5 parts cement.
Total number of parts in every load = 8 + 7 + 5 = 20 parts
If total load = 220 kg, then 20 parts = 220 kg
Divide each side by 20 : 1 part = 11 kg
gravel = 8 parts = 8 x 11 kg = <em>88 kg</em>
water = 7 parts = 7 x 11 kg = <em>77 kg</em>
cement = 5 parts = 5 x 11 kg = <em>55 kg</em>
<u>Check:</u> 88 + 77 + 55 = 220 yay !