Complete question :
A company has two manufacturing plants with daily production levels of 5x + 11 items and 2x - 3 items, respectively, where x represents a minimum quantity. The first plant produces how many more items daily than the second plant?
Answer:
3x + 14
Step-by-step explanation:
Given that:
Production level of plant 1 = 5x + 11
Production level of plant 2 = 2x - 3
The first plant produces how many more items daily than the second plant :
Plant 1 production - plant 2 production
(5x + 11) - (2x - 3)
Open the bracket :
5x + 11 - 2x + 3
5x - 2x + 11 + 3
3x + 14
Daily production of plant 1 exceeds that of plant 2 by 3x + 14
Answer:
(7 x - 1) (x + 1)
Step-by-step explanation:
Factor the following:
7 x^2 + 6 x - 1
Factor the quadratic 7 x^2 + 6 x - 1. The coefficient of x^2 is 7 and the constant term is -1. The product of 7 and -1 is -7. The factors of -7 which sum to 6 are -1 and 7. So 7 x^2 + 6 x - 1 = 7 x^2 + 7 x - x - 1 = (7 x - 1) + x (7 x - 1):
(7 x - 1) + x (7 x - 1)
Factor 7 x - 1 from (7 x - 1) + x (7 x - 1):
Answer: (7 x - 1) (x + 1)
Answer:
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