Answer:
The time interval when 
is at 
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :
So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between 
The schematic free body graphical representation of the above illustration was attached in the file below and the point when is at 4 is obtained in the parabolic curve.
So, is at
Taking the integral of the time interval in order to determine the distance; we have:
distance = 
= 
= By using the Scientific calculator notation;
distance = 106.109 m
Answer:
10 x 10 x 10 x 10 x 10 = 100000
6 x 6 x 6 = 216
4 x 4 x 4 x 4 = 256
2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 1024 / or if the number was 21 x 0 then the answer = 1
Step-by-step explanation:
I already wrote the explanation in the answer but I'm guessing the number you put beside the first number is the exponent. So as you can see 73 = 7 mulitiplying by itself 3 times. The number 3 is an exponent because it tells you how many times you're multiplying the number by itself. If you continue doing that then you will get the same answer as I did. Good luck!
Answer:
n=0
Step-by-step explanation:
Clear parenthesis w/ distribution:
3(-7n+1)=-21n+3
Move everything over to one side:
6n+3=-21n+3
6n=21n Subtract the 3 on the right.
-15n=0 Subtract the 21.
n=0 Divide the -15.
