Answer:
x^2+11x+10
or
(x+1)(x+10) since you can factor x^2+11x+10
Step-by-step explanation:
Let's do synthetic division.
We are dividing by x+2, so -2 will be on the outside. Like this:
-2 | 1 13 32 20
| -2 -22 -20
|___________________________
1 11 10 0
The remainder is 0, so (x+2) is indeed a factor of x^3+13x^2+32x+20.
The other factor we found by doing this is (x^2+11x+10).
You can find more factors by factoring x^2+11x+10.
Two numbers that multiply to be 10 and add to be 11 is 10 and 1 so the factored form of x^2+11x+10 is (x+10)(x+1).
If

, then any ordered pair would satisfy the equation.
Since we're not given the ordered pairs, then this is the only information I can give to you.
Answer:
Reflexive Property
Step-by-step explanation:
For all real numbers x , x=x . A number equals itself
we know that
For a polynomial, if
x=a is a zero of the function, then
(x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.
So
In this problem
If the cubic polynomial function has zeroes at 2, 3, and 5
then
the factors are

Part a) Can any of the roots have multiplicity?
The answer is No
If a cubic polynomial function has three different zeroes
then
the multiplicity of each factor is one
For instance, the cubic polynomial function has the zeroes

each occurring once.
Part b) How can you find a function that has these roots?
To find the cubic polynomial function multiply the factors and equate to zero
so

therefore
the answer Part b) is
the cubic polynomial function is equal to

Answer:
2500 Square meters
Step-by-step explanation:
Given the garden area (as a function of its width) as:

The maximum possible area occurs when we maximize the area. To do this, we take the derivative, set it equal to zero and solve for w.
A'(w)=-2w+100
-2w+100=0
-2w=-100
w=50 meters
Since Marquise has 200 meters of fencing to build a rectangular garden,
Perimeter of the proposed garden=200 meters
Perimeter=2(l+w)
2(l+50)=200
2l+100=200
2l=200-100=100
l=50 meters
The dimensions that will yield the maximum area are therefore:
Length =50 meters
Width=50 meters
Maximum Area Possible =50 X 50 =<u>2500 square meters.</u>