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Snowcat [4.5K]
4 years ago
15

A linear equation has more than one y intercept.what can you conclude about the graph of the equation?

Mathematics
2 answers:
Sever21 [200]4 years ago
8 0
I'd say the graph isn't functional
son4ous [18]4 years ago
5 0
A line can be determined with two points.

The y-intercept is where a graph intersects the y axis.

Let 2 points lie on the y axis. Those are the y-intercepts.

2 lines can only have 0 intersections, 1 intersection, or infinitely many intersections.

Thus, if a line intersects another line more than 2 times, both lines must be the same line.

Using that information to create a line, you would have the line x=0.

x=0 is a vertical line that intersects the y-axis infinitely many times since they are the same line.

However, x=0 is not a function.

Have an awesome day! :)
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2 years ago
A restaurant wants to gather data about a new dish by giving out free samples and asking for feedback. Who should the restaurant
mote1985 [20]

The restaurant would have to give the free samples to its customers so that they would provide a feedback for the business.

<h3>What is feedback?</h3>

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2 years ago
What does 6 8/15 + 7 4/5=
tatuchka [14]

Answer:

It equals 14 1/3

hope this helps!!

5 0
3 years ago
Julie has basketball practice every 6 days and track practice every 4 days. In how many days will she have both basketball and t
GrogVix [38]

Answer: 12 days

Step-by-step explanation:

For us to know the number of days whereby Julie will have both basketball and track practice, we've to find the lowest common multiple of both 6 and 4. This will be:

Multiples of 4 = 4, 8, 12, 16, 24.

Multiples of 6 = 6, 12, 18, 24, 30.

The lowest common multiple is 12. Therefore, she'll have basketball and track practice in 12 days

5 0
3 years ago
A company determined that the marginal​ cost, C' (x )of producing the xth unit of a product is given by C' (x )= x^3- 6x. Find t
Rashid [163]

Answer:

C(x) = \frac{x^4}{4}-3x^2+3,000

Step-by-step explanation:

The marginal cost function, C'(x), is the derivate of the cost function, C(x).

Therefore, we can obtain the cost function by finding the integral of the marginal cost function:

C(x) = \int\ {C'(x)} \, dx \\C(x) = \int\ {(x^3-6x)} \, dx \\C(x) = \frac{1}{4} x^4-3x^2+a

Where 'a' is a constant and represents fixed costs. If fixed costs are $3,000, the cost function is:

C(x) = \frac{x^4}{4}-3x^2+3,000

3 0
3 years ago
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