Answer:

Step-by-step explanation:
From figure,

In triangle 

![\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]](https://tex.z-dn.net/?f=%5CRightarrow%20%28a%2Bb%29%5E2%3D%28a-b%29%5E2%2B%28O%27%20D%29%5E2%5C%5C%5CRightarrow%20a%5E2%2Bb%5E2%2B2ab-a%5E2-b%5E2%2B2ab%3D%28O%27%20D%29%5E2%5C%5C%5CRightarrow%204ab%3D%28O%27%20D%29%5E2%5C%5C%5CRightarrow%20O%27D%3D2%5Csqrt%7Bab%7D%20%5C%5C%5CRightarrow%20O%27%20D%3D2%5Csqrt%7Bab%7D%3DAB%20%5Cquad%20%5Cquad%20%5B%5Cbecause%20O%27%20DAB%5C%3B%5C%3B%20%5Ctext%7Bis%20a%20rectangle.%7D%5D)
Hence, 
Answer:
Ex = - 4 + 14xy
Ey = 7x² - 7z²
Ez = -14yz
Step-by-step explanation:
The relationship between Electric field Er(x, y, z) and Electric potential, V, is a differential relationship:
Er(x, y, z) = -dV/dr(x, y, z)
Where r(x, y, z) = distance in x, y and z components.
The x component of the electric field is:
Ex = -dV/dx
Given that:
V = 4x - 7x²y + 7yz²
Ex = -dV/dx
Ex = -(4 - 14xy)
Ex = -4 + 14xy
The y component of the electric field is:
Ey = -dV/dy
Ey = -(-7x² + 7yz²)
Ey = 7x² - 7z²
The z component of the electric field is:
Ez = -dV/dz
Ez = -(14yz)
Ez = -14yz
(3^3)* (3^-3)= 3^0
Remember that if you have the same base, add the exponents.
3^0=1
5(1)=5
Final answer: 5
Answer:
is the answer.
Step-by-step explanation:
We have to solve the given expression 2 × 1 - 2 3/8

[Now we take LCF of denominators of both the fractions]

So the final answer is 