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3 years ago

Line GH contains points G(–2, 6) and H(5, –3). What is the slope of ?

Mathematics

2 answers:

Anon25 [30]3 years ago

4 0

Answer:

$\Huge\boxed{\mathsf{-\frac{9}{7} }}}$

Step-by-step explanation:

SLOPE FORMULA:

$\displaystyle \mathsf{\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN} }$

Y2=(-3)

Y1=6

X2=5

X1=(-2)

Solve.

$\displaystyle \mathsf{\frac{(-3)-6}{5-(-2)}=\frac{(-3)-6}{5+2}= \frac{-9}{7}=\boxed{\mathsf{-\frac{9}{7}} }}$

The slope is -9/7.

igor_vitrenko [27]3 years ago

4 0

Answer:

The answer is B

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2. A student on the track team runs 45 minutes each day as a part of her training. She

fomenos

Answer:

Step-by-step explanation:

The basic equation to solve this would be D = RT, which is

D is Distance

R is Rate (speed)

T is time

To find total distance D, we can find individual distances for two legs of the whole.

First Leg:

R = 8

T = a

D = 8a

Second Leg:

R = 7.5

T = b

D = 7.5b

Total distance D is:

D = 8a + 7.5b

Moreover, we know student runs 45 minutes in total hence a + b = 45 or we can say a = 45 - b, so we can replace this in the equation found:

D = 8a + 7.5b

D = 8(45 - b) + 7.5b

Answer choice D is right.

8 0

3 years ago

Evgen [1.6K]

Answer:

Null hypothesis $H_0; \mu=5$

Alternative hypothesis $H_a; \mu\neq 5$

Step-by-step explanation:

Consider the provided information.

The shower by an adult is 5 minutes.

The mean amount of time that college students spend in the shower is significantly different from 5 minutes. In a sample of 15 students, he found the average time was 4.29 minutes and the standard deviation was 0.75 minutes.

We need to determine the appropriate null and alternative hypotheses.

A null hypothesis is there is no statistical significance between the two variables.

An alternative hypothesis is there is a statistically significant relationship between two variables.

Therefore the required null and alternative hypothesis are:

Null hypothesis $H_0; \mu=5$

Alternative hypothesis $H_a; \mu\neq 5$

3 0

3 years ago

Can I Get Help On This Question?

Gnoma [55]

I believe it would just be -1

3 0

3 years ago

How to calculate distance between two points (-3,2) and (3,0). And pls find the radical

irina1246 [14]

√74
Explanation:
To calculate the distance use the
distance formula
d=√(x2−x1)^2+(y2−y1)^2

−−−2
where
(x1,y1)and (x2,y2)
are 2 coordinate points
The 2 points here are (-3 ,7) and (4 ,2)
let(x1,y1)=(−3,7) and (x2,y2)=
(4,2)⇒d=√(4−(−3))2+(2−7)2=√49+25=√74←in radical form

7 0

2 years ago

Read 2 more answers

What is the equation of the quadratic graph with a focus of (6, 0) and a directrix of y = −10 ?

Mademuasel [1]

Answer:

$(x-6)^{2}=20(y+5)^{2}$

Step-by-step explanation:

The standard for for the equation of a parabola is $(x-h)^{2}=4p(y-k)$

The focus is given as $(h, k+p)$

The directrix is given by $y=k-p$

Comparing focus given as $(6,0)$ to formula of focus $(h,k+p)$ , we see that $h=6$ and $k+p=0$
Comparing directrix given as $y=-10$ to formula of directrix $y=k-p$ , we can write $k-p=-10$

We can use the two system of equations [ $k+p=0$ and $k-p=-10$ ] to solve for $k$ and $p$ .

Adding the two equations gives us:

$2k=-10\\k=\frac{-10}{2}\\k=-5$

Using this value of $k$ , we can find $p$ by plugging this value in either equation. Let's put it in Equation 1. We have:

$k-p=-10\\-5-p=-10\\-5+10=p\\p=5$

Now, that we know $h=6$ , $k=-5$ , and $p=5$ , we can plug these values in the standard form equation to figure out the parabola's equation. Doing so and rearranging gives us:

$(x-6)^{2}=4(5)(y-(-5))^{2}\\(x-6)^{2}=20(y+5)^{2}\\$

This is the equation of the parabola with focus $(6,0)$ and directrix $y=-10$

3 0

3 years ago

Read 2 more answers