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3 years ago

14

Line GH contains points G(–2, 6) and H(5, –3). What is the slope of ?

2 answers:

Anon25 [30]3 years ago

4 0

Answer:

$\Huge\boxed{\mathsf{-\frac{9}{7} }}}$

Step-by-step explanation:

<u><em>SLOPE FORMULA:</em></u>

$\displaystyle \mathsf{\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN} }$

Y2=(-3)

Y1=6

X2=5

X1=(-2)

Solve.

$\displaystyle \mathsf{\frac{(-3)-6}{5-(-2)}=\frac{(-3)-6}{5+2}= \frac{-9}{7}=\boxed{\mathsf{-\frac{9}{7}} }}$

The slope is -9/7.

igor_vitrenko [27]3 years ago

4 0

Answer:

The answer is B

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3 years ago

A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha

netineya [11]

Answer:

$(a)\ Area = 195\pi$

$(b)\ Volume = 700\pi$

Step-by-step explanation:

Given

$h = 12$

$d_1 = 10$ --- lower diameter

$d_2 = 20$ --- upper diameter

Solving (a): The curved surface area

This is calculated as:

$Area = \pi l(r_1 + r_2)$

Where

$r_1 = 0.5 * d_1 = 0.5 * 10 = 5$ --- lower radius

$r_2 = 0.5 * d_2 = 0.5 * 20 = 10$ --- upper radius

And

$l = \sqrt{h^2 + (r_1 - r_2)^2$ ---- l represents the slant height of the frustrum

$l = \sqrt{12^2 + (5 - 10)^2$

$l = \sqrt{12^2 + (-5)^2$

$l = \sqrt{144 + 25$

$l = \sqrt{169$

$l = 13$

So, we have:

$Area = \pi l(r_1 + r_2)$

$Area = \pi * 13(5 + 10)$

$Area = \pi * 13(15)$

$Area = 195\pi$

Solving (b): The volume

This is calculated as:

$Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))$

This gives:

$Volume = \frac{1}{3}\pi * 12 * (5^2 + 10^2 + (5 * 10))$

$Volume = \frac{1}{3}\pi * 12 * (25 + 100 + (50))$

$Volume = \frac{1}{3}\pi * 12 * (175)$

$Volume = \pi *4 * 175$

$Volume = 700\pi$

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2 years ago

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2 years ago

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valentina_108 [34]

Answer:

£2720

Step-by-step explanation:

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100%=x

106x=288320

divide both by 106 it gives 2720

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2 years ago

Mrs Omar runs the school tennis club. She has a bin of tennis balls and rackets for every 5 tennis balls in the bin there are 5

Sav [38]

Answer:

x=y

Step-by-step explanation:

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2 years ago

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