Question

1. What is the relative maximum and minimum of the function?

Answer 1

Take the derititve

f'(x)=3x^2+6x-24
set to zero
0=3(x^2+2x-8)
0=3(x-2)(x+4)
at x=2 and -4

those are where the min and max are

ok so
sign chart
to the lft of -4, the sign is positive
betweeen -4 and 2, the sign is negative
tothe right of 2 the sign is positive


max=sign changef from (+) to (-)
min=sign change from (-) to (+)

so max at x=-4 and min at x=2

find x=2, the value is -28

answer is C










2. 4th degree so quartic (qua, like quad or quadrilatal)