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3 years ago

12

If there is thirtysix times it by 1 million how much will that be

2 answers:

alexira [117]3 years ago

8 0

Answer:

36*1 000 000

=36 000 000

Step-by-step explanation:

REY [17]3 years ago

8 0

It would be 36,000,000 cause u add the zeros from the million

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Write 0.8 as a fraction. A)29 B)49 C)79 D)89

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79
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3 years ago

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Angie mixes 7 2/3 pints fruit juice and 3 1/4 pint sprite to make punch far a party. she has 6 pints left at the end of the part

lana66690 [7]

Answer:

16 11/12

Step-by-step explanation:

7 2/3 + 3 1/4 =

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2 years ago

Cheryl purchased a pool for $8,960 using a six-month deferred payment plan with an interest rate of 27.35%. She did not make any

kotykmax [81]

First find the amount at the end of the deferment period using the formula of the future value of a compound interest
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3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

Last math question. 6th grade math

Karolina [17]

Answer:

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2 years ago

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