3 years ago

Find an equation in slope intercept form of the line that has slope four and passes through point A (3, -4)

Mathematics

1 answer:

tatiyna3 years ago

4 0

Answer:

Step-by-step explanation:

y + 4 = 4(x - 3)

y + 4 = 4x - 12

y = 4x - 16

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Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia

GrogVix [38]

Answer:

$(\frac{dy}{dt})^2=sin^2t$

Step-by-step explanation:

$y=cost$

DE : $(\frac{dy}{dt})^2=1-y^2$

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

$\frac{dy}{dt}=-sint$

Using the formula

$\frac{d(cosx)}{dx}=-sinx$

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RHS

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By using the formula

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LHS=RHs

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$(\frac{dy}{dt})^2=sin^2t$

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What is the difference between 3/7, and 1/14

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Determine the length and midpoint of the segment whose endpoints are (–15, 9) and (–4, 11).

ch4aika [34]

$(-15,9) \\
x_1=-15 \\
y_1=9 \\ \\
(-4,11) \\
x_2=-4 \\
y_2=11 \\ \\
\hbox{the length:} \\
l=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(-4+15)^2+(11-9)^2}=\\
=\sqrt{11^2+2^2}=\sqrt{121+4}=\sqrt{125}=\sqrt{25 \times 5}=5\sqrt{5} \\ \\
\hbox{the midpoint:} (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}) \\
\frac{x_1+x_2}{2}=\frac{-15-4}{2}=\frac{-19}{2}=-9.5 \\
\frac{y_1+y_2}{2}=\frac{9+11}{2}=\frac{20}{2}=10 \\
(-9.5,10)$

The length of the segment is 5√5, the midpoint of the segment is (-9.5,10).

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3 years ago

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