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AfilCa [17]
3 years ago
14

How much do you need to subtract from 31/6 to make 5

Mathematics
1 answer:
matrenka [14]3 years ago
6 0

Answer:

1/6

3/10

1 7/8

1 6/7

1 5/9

should be anyway

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40.00 for premium - 15.00 more than standard
40-15=35.00 for standard
4 0
3 years ago
Using the distributive property rewrite 2x + 16 as a product of two factors
tresset_1 [31]
2(x + 8)
Factor out the 2
5 0
3 years ago
I need some help and can you please show your work? Thank you have a good day
SVEN [57.7K]
$1.75

If 4 lemons altogether cost $7, you want to divide the price by 4 to find the price for one single lemon.

7/4 = $1.75

Now if you buy 4 lemons that cost $1.75, your total will add up to $7
3 0
3 years ago
The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi
storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

V = \frac{1}{3}\pi r^{2}h

Differentiate the equation with respect to time t, such that

\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)

To differentiate the product,

Let r² = u, so that

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)

Then, using product rule

\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]

Since u = r^{2}

Then, \frac{du}{dr} = 2r

Using the Chain's rule

\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}

∴ \frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]

Then,

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

Now,

From the question

\frac{dr}{dt} = 7 m/min

\frac{dV}{dt} = 236 m^{3}/min

At the instant when r = 99 m

and V = 180 m^{3}

We will determine the value of h, using

V = \frac{1}{3}\pi r^{2}h

180 = \frac{1}{3}\pi (99)^{2}h

180 \times 3 = 9801\pi h

h =\frac{540}{9801\pi }

h =\frac{20}{363\pi }

Now, Putting the parameters into the equation

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]

236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]

708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}

708 = 30790.75 \frac{dh}{dt} + 76.36

708 - 76.36 = 30790.75\frac{dh}{dt}

631.64 = 30790.75\frac{dh}{dt}

\frac{dh}{dt}= \frac{631.64}{30790.75}

\frac{dh}{dt} = 0.021 m/min

Hence, the rate of change of the height is 0.021 meters per minute.

3 0
3 years ago
The sum of the angle measures of a triangle is 180°. Find the value of x . Then find the angle measures of the triangle.
Lady bird [3.3K]

Answer:

Step-by-step explanation:

The sum of the angle measures of a triangle is 180°. Find the value of x . Then find the angle measures of the triangle.

find the value of x

x + 2x + x + 8 = 180

4x = 180 - 8

4x = 172

x = 172 : 4

x = 43

find angles

2x = 43 * 2

2x = 86°

-------

x = 43°

--------

x + 8 = 43 + 8

x = 51°

-----------------------

check

86 + 43 + 51 = 180°

the answer is good

6 0
2 years ago
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