How much do you need to subtract from 31/6 to make 5

Find the measures of the unknown angles in the triangle shown. Round it the nearest degree.

Fudgin [204]

Answer:

x = 49°

y = 41°

Step-by-step explanation:

Recall: SOH CAH TOA

✔️To find x, the trig function we would apply is Cos, which is:

Cos θ = Adjacent/Hypotenuse (CAH)

θ = x

Adjacent = 13

Hypotenuse = 20

$Cos(x) = \frac{13}{20}$

$x = cos^{-1}(\frac{13}{20})$

x = 49.4583981°

x = 49° (nearest degree)

✔️To find y, the trig function we would apply is Sin, which is:

Sin θ = Opposite/Hypotenuse (SOH)

θ = y

Opposite = 13

Hypotenuse = 20

$Sin(y) = \frac{13}{20}$

$y = Sin^{-1}(\frac{13}{20})$

y = 40.5416019°

y = 41° (nearest degree)

3 0

3 years ago

Plz help... geometry volume, density

Ivenika [448]

From what I'm understanding of these questions, the biggest thing you need to answer these is the formulas for cylinders and triangular prisms. I'm not sure what the quantities are for either question so I'm going to work with made up numbers to give examples for the formulas. For number 2 with the cylinder, let's consider the formula first:

π × r2 × h <em>OR </em>pi (3.14) times radius squared times height

If you have the height and you have pi, all you need to take is the doubled radius (aka multiply it by 2) and plug that back into the formula. For the sake of an example, I'm going to make up the number 2 for the radius and 6 for the height. Here's what that would look like:

r = 2; double it, resulting in 4

pi x 4^2 x 6

3.14 x 16 x 6

= 301.44

Work with the actual numbers you have and you're good to go.

For number 3, reducing something by 1/2 means dividing by 2. Let's consider the formula and then work through another example:

1/2 x b x h x l <em>OR </em> 1/2 times base times height times length

For the sake of an example, I'll use 10 for the height, 15 for the base, and 20 for the length:

h = 10; reduce by 1/2, resulting in 5

1/2 x 15 x 5 x 20

= 750

Plug in your actual quantities, and remember your volume units. Hope this helps!