Answer:
number of sheep with homozygous dominant white fat genotype = 5399
Explanation:
If p = frequency of dominant allele and q= frequency of recessive allele
According to Hardy-Weinberg equilibrium:
p + q =1 and p² + 2pq + q² = 1
where p² = frequency of homozygous dominant genotype
q²= frequency of homozygous recessive genotype
and 2pq= frequency of heterozygous genotype
Here,
q² = 53/6520= 0.0081
q = √0.0081 = 0.09
p = 1-q = 1-0.09= 0.91
So, p² = 0.91² = 0.8281
number of sheep with homozygous dominant white fat genotype= 0.8281*6520 = 5399
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because the flowering plant is very important
if you don't make it
you may damage them
good lucks :)
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