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shepuryov [24]
3 years ago
6

A number, y, is equal to the difference of a larger number and 3. The same number is one-third of the sum of the larger number a

nd 9. Which equations represent the situation? x + y = 3 and x minus 3 y = negative 27 x + y = 3 and x minus 3 y = negative 9 x minus y = 3 and x minus 3 y = negative 27 x minus y = 3 and x minus 3 y = negative 9
Mathematics
2 answers:
mariarad [96]3 years ago
4 0

Answer:

The two equations are

y = x - 3 and

3y = x + 9

Step-by-step explanation:

The options are not well stated. I'll answer the question without the options but however, my answer will be a reflection of one of the given options.

Given:

2 statements

Required

Write equivalent of both statements as equations

Let the large number be represented by x.

From the first statement (y, is equal to the difference of a larger number and 3)

Difference means minus (-); so, this statement is represented as follows to give us the first equation:

y = x - 3

From the second statement (The same number is one-third of the sum of the larger number and 9).

This is also represented as follows to give us the second equation

y = ⅓(x + 9)

Multiply both sides by 3

3 * y = 3 * ⅓(x + 9)

3y = x + 9

So, the two equations are

y = x - 3 and

3y = x + 9

Contact [7]3 years ago
3 0

Answer:

The two equations are

y = x - 3 and

3y = x + 9

Step-by-step explanation:

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The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran
VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, X = "Comprehensive strength of concrete". We have information that X is normally distributed with a mean of 2500 psi and a standard deviation of  50 psi (or a variance of 2500 psi). In other words, X \sim N(2500, 2500).

We want to know the probability of the mean of X or \bar{X} that falls in the interval [2499;2510]. From inference theory we know that :

\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)

Now we can find the probability as follows:

P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )

Where Z \sim N(0,1), then:

P(-0.002 \leq Z \leq 0.02 ) \approx P(0 \leq Z \leq 0.02 ) = P(Z \leq 0.02 ) - P(Z \leq 0) \\P(0 \leq Z \leq 0.02 ) = 0.50798 - 0.5 = 0.00798

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Answer:

Bob could predict a <u>100%</u>, as if he has studied for a long time, and has learnt the content, he should be able to get 100%!

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RideAnS [48]
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Answer:

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Step-by-step explanation:

The communitive property of addition states that no matter what order of the numerical values the answer will be the same. hope this helps

8 0
3 years ago
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