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Pie
3 years ago
5

There are two coins, one is fair and one is biased. The biased coin has a probability of landing on heads equal to 4/5. One of t

he coins is chosen at random (50-50), and is flipped repeatedly until it lands on tail. If it landed on heads 4 times before landing on tails, what is the posterior probability that coin chosen was biased?
Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

72.4%

Step-by-step explanation:

The probability of A occurring given that B occurs = the probability of both A and B / the probability of B

P(A|B) = P(A∩B) / P(B)

This can be rearranged as:

P(A∩B) = P(B) P(A|B)

In this case:

A = biased coin is chosen

~A = fair coin is chosen

B = 4 heads then 1 tail

First, let's find P(A∩B).

P(A∩B) = P(B) P(A|B)

P(A∩B) = ½ × ₅C₄ (⅘)⁴ (⅕)¹

P(A∩B) = 0.2048

Next, find P(~A∩B).

P(~A∩B) = P(B) P(~A|B)

P(~A∩B) = ½ × ₅C₄ (½)⁴ (½)¹

P(~A∩B) = 0.078125

Therefore, the probability that the coin is biased is:

P = P(A∩B) / (P(A∩B) + P(~A∩B))

P = 0.2048 / (0.2048 + 0.078125)

P = 0.723866749

The probability is approximately 72.4%.

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ycow [4]

Answer: The tenth term is 76

=======================================================

Explanation:

We use this arithmetic sequence formula to get the nth term

a_n = a_1 + d(n-1)

Plug in a_1 = 4, \ d = 8, \ n = 10 and you should get the following:

a_n = a_1 + d(n-1)\\\\a_{10} = 4 + 8(10-1)\\\\a_{10} = 4 + 8(9)\\\\a_{10} = \textbf{76}\\\\

The tenth term is <u>76</u>

---------

We can verify this by listing out the terms one by one. Start at 4, add on 8 each time, until you generate the 10th term. A table like the one shown below is a good way to keep track of all the terms.

\begin{array}{c|c}\boldsymbol{n} & \boldsymbol{a_n}\\1 & 4\\2 & 12\\3 & 20\\4 & 28\\5 & 36\\6 & 44\\7 & 52\\8 & 60\\9 & 68\\10 & \textbf{76}\\\end{array}

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In short, the error is with the "10" in the expression 4+10(8). The student should have used 9 instead. This is because of the n-1 term in a_n = a_1 + d(n-1) which shifts everything one spot to the left.

7 0
2 years ago
Yogi is 6 years older than Michelle. The sum of their ages is 26. Write a system of linear equations to represent this informati
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Answer:

10 and 16, x+(x+6)=26

Step-by-step explanation:

Michelle has an age we don't know, so we put her age as x.

Yogi is 6 years older than her, so her age is x+6

Michelle=x

Yogi=x+6

we know both their ages equal 26. so we set it up as

x+(x+6)=26

combining like terms we get

2x+6=26

subtract 6 from both sides

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divide both sides by 2

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now that we have the value for x, we plug it into their original ages

Michelle is 10, because her age is just x.

Yogi is 16, because her age is x+6

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3 years ago
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Answer:

x = - 1

Step-by-step explanation:

Given

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6 0
3 years ago
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valentina_108 [34]
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Answer:

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Step-by-step explanation:

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