Ask question

Ask question

All categories

3 years ago

9

For each of these intervals, list all its elements or explain 2.1 Sets 131 why it is empty. a) [a,a] c) (a, a] e) (a,b), where a

> b b) [a,a) d) (a, a) f) [a,b],wherea>b

1 answer:

stepan [7]3 years ago

6 0

Answer: b

Step-by-step explanation:

You might be interested in

Please help!!!! i am despite, i will mark brainlyest

Sedaia [141]

Answer:

x=12

10x = 120

5x = 60

Step-by-step explanation:

paralellograms will become 360 degrees

so 2(5x) +2(10x)= 360

Simplify:

10x + 20x = 360

= 30x

divide both sides by 30 and isolate

<u>30x </u> = <u>360</u>

30 30

x=12

multiply 12 by 10x and 5x

10x = 120

5x = 60

7 0

3 years ago

Can someone help me with this question? I seem to be getting a negative answer every time :(

NeX [460]

Substitute 4 for y. Then -3x^2 + 16 = 52.

Solve for x. Subtract 16 from both sides, obtaining -3x^2 = 36.

Divide both sides by -3, obtaining x^2 = -12. This last result makes no sense, as no square of a real number could be negative. Probably this is where you're ":getting a negative answer."

If imaginary answers were allowed, then x = i*√12 = i*2√3 or x = -i*2√3.

x =

8 0

3 years ago

Read 2 more answers

You know whats up, please help me ahha.

Rom4ik [11]

Answer:

0.07

Step-by-step explanation:

0.07 - quotient

____

4/0.28 - divided

l

divisor

4 0

2 years ago

What is 1/6 + 1/4 + 1/3

IgorC [24]

The answer is 9/12

Brainliest pls

6 0

3 years ago

Read 2 more answers

A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not. Determ

Hunter-Best [27]

Answer:

The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not.

This means that $n = 100, \pi = \frac{20}{100} = 0.2$

68% confidence level

So $\alpha = 0.32$ , z is the value of Z that has a pvalue of $1 - \frac{0.32}{2} = 0.84$ , so $Z = 0.995$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 - 0.995\sqrt{\frac{0.2*0.8}{100}} = 0.16$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 + 0.995\sqrt{\frac{0.2*0.8}{100}} = 0.24$

The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).

4 0

3 years ago