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dolphi86 [110]
3 years ago
13

7. The largest of the Great Pyramids in Egypt was built with a square base,

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:

Difference between the original and current volumes = 4013140.30 cubic feet

Step-by-step explanation:

Largest pyramid has the square base with one edge = 754 feet

Area of the square base = (Side)²

                            = (754)²

                            = 568516 square feet

Volume of the pyramid = \frac{1}{3}(\text{Area of the base})(\text{Height})

                                       = \frac{1}{3}\times 568516\times 481

                                       = 91152065.3 cubic feet

After erosion,

Area of the base = (745)² = 555025 square feet

Volume of the pyramid = \frac{1}{3}(555025)(471)

                                       = 87138925 cubic feet

Difference between the original and current volumes of the pyramid

= 91152065.30 - 87138925

= 4013140.30 cubic feet

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Answer:

D) C': ( -3, -2), D': ( -4, 1), E': ( -1, -2)

Step-by-step explanation:

Formula for this equation:

(x - 5, y - 3)

C:

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(x - 5, y - 3)

C': ( -3, -2)

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E': ( -1, -2)

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poizon [28]

Answer:

Step-by-step explanation:

I believe it's 9 to the west

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3 years ago
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dlinn [17]

Answer

D. 3m - 4/3 -2/m


<u>Explanation</u>

(9m²-4m-6) ÷ 3m  = 9m²/3m - 4m/3m - 6/3m

Carry out the division, each term is divided by 3m.

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Finally you will get,

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5 0
3 years ago
A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la
SOVA2 [1]

Answer:

8\pi\text{ square cm}

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

S=2\pi rh

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

4^2 = (2r)^2 + h^2   ( see in the below diagram ),

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16 - 4r^2 = h^2

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Thus, the surface area of the cylinder,

S=2\pi r(\sqrt{16-4r^2})

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\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})

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Again differentiating with respect to r,

\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})

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8r^2 = 16

r^2 = 2

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Since, for r = √2,

\frac{d^2S}{dt^2}=negative

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

S = 2\pi (\sqrt{2})(\sqrt{16-8})

=2\pi (\sqrt{2})(\sqrt{8})

=2\pi \sqrt{16}

=8\pi\text{ square cm}

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3 years ago
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kaheart [24]

Answer:

1

Step-by-step explanation:

f(n) = 3n

f(1/3)= 3*(1/3)=1

f(1/3)=1

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