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Debora [2.8K]
4 years ago
12

Simplify. 7 – 2 • 5 + 9 • 3 A. 18 B.102 C.24 D.–30

Mathematics
2 answers:
avanturin [10]4 years ago
5 0
7-2*5+9*3=7-10+27=24

C)24
MAVERICK [17]4 years ago
4 0
<span>⇒ </span>Solution
 1) Simplify <span>2×5</span> to 10
<span>7−10+9×3

2) </span><span>Simplify </span><span>9×3</span><span> </span><span>to</span><span> </span><span>27</span><span>7</span><span>−</span><span>10</span><span>+</span><span>27

3) Answer 
24

The answer = C</span>
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5 0
3 years ago
A researcher wants to determine whether the number of minutes adults spend online per day is related to gender. A random sample
suter [353]

Answer:

The expected frequency for the cell E2,2 is = 33

Step-by-step explanation:

The given data is

Gender               | 0-30| 30-60| 60-90| 90+       Totals

Male                    | 23    |    35   |   76    |  46        180

<u> Female               |   31   |    42   |   46    |  16         135    </u>

<u>Totals                    54         77        122    62          315  </u>

<u />

The expected frequency for the cell E2,2 is :

Expected for the (30-60 box for females)   =  Total of (30-6)/ (total )* females

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Here p= 77/315 and n= 135

therefor X= pn = 33

χ²=  (33-42)²/33= 2.455  ( for the single value of E2,2=33)

Expected for the (30-60 box for males)   =  Total of (30-6)/ (total )* males

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χ²=  (44-42)²/44= 0.09

The critical region is  χ² (0.05) 3 ≥  χ²= 11.34

Let the null and alternate hypothesis be

H0:the number of minutes spent online per day is not related to gender

against

Ha: the number of minutes spent online per day is related to gender

The single value of χ² for E2,2 = 2.45 is less than the critical value of 11.34.  

6 0
3 years ago
*****BRAINLIEST AVAILABLE********
sweet-ann [11.9K]

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                        ÷9               ÷9

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*******************************************************************************

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Answer:

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