All categories

3 years ago

WHAT IS 41SQUARED PLUS XSQUARED +213?

Mathematics

1 answer:

Bingel [31]3 years ago

4 0

Answer:

1894+x^2

Step-by-step explanation:

1894+x^2

41 squared IS 1,681.

Adding 213 makes it 1894.

And you end up with the expression 1894+x^2

Hope this helps!

You might be interested in

At a coffee shop, the first 100 customers'

Paladinen [302]

$\frac{1}{5}$

Step-by-step explanation:

cold =25

large=5

$\frac{5}{25}$

divide it

$\frac{1 }{5}$

8 0

2 years ago

PLEASE HELP !! ILL GIVE 40 POINTS ; PLUS BRAINLIEST !! DONT SKIP ANSWER.

Natalija [7]

Answer:
GFC and BCF ??

8 0

3 years ago

A trough has ends shaped like isosceles triangles, with width 5 m and height 7 m, and the trough is 12 m long. Water is being pu

Svet_ta [14]

Answer:

$\dfrac{dh}{dt}=21 \text{m/min}$

the rate of change of height when the water is 1 meter deep is 21 m/min

Step-by-step explanation:

First we need to find the volume of the trough given its dimensions and shape: (it has a prism shape so we can directly use that formula OR we can multiply the area of its triangular face with the length of the trough)

$V = \dfrac{1}{2}(bh)\times L$

here L is a constant since that won't change as the water is being filled in the trough, however 'b' and 'h' will be changing. The equation has two independent variables and we need to convert this equation so it is only dependent on 'h' (the height of the water).

As its an isosceles triangle we can find a relationship between b and h. the ratio between the b and h will be always be the same:

$\dfrac{b}{h} = \dfrac{5}{7}$

$b=\dfrac{5}{7}h$ this can be substituted back in the volume equation

$V = \dfrac{5}{14}h^2L$

the rate of the water flowing in is:

$\dfrac{dV}{dt} = 6$

The question is asking for the rate of change of height (m/min) hence that can be denoted as: $\frac{dh}{dt}$

Using the chainrule:

$\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}$

the only thing missing in this equation is dh/dV which can be easily obtained by differentiating the volume equation with respect to h

$V = \dfrac{5}{14}h^2L$

$\dfrac{dV}{dh} = \dfrac{5}{7}hL$

reciprocating

$\dfrac{dh}{dV} = \dfrac{7}{5hL}$

plugging everything in the chain rule equation:

$\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}$

$\dfrac{dh}{dt}=\dfrac{7}{5hL}\times 6$

$\dfrac{dh}{dt}=\dfrac{42}{5hL}$

L = 12, and h = 1 (when the water is 1m deep)

$\dfrac{dh}{dt}=\dfrac{42}{5(1)(12)}$

$\dfrac{dh}{dt}=21 \text{m/min}$

the rate of change of height when the water is 1 meter deep is 21 m/min

6 0

3 years ago

Read 2 more answers

21. The midpoint of UV is (5,-11). The coordinates of one endpoint are U(3,5). Find the coordinates of endpoint V.

natima [27]

I hope this helps you

7 0

3 years ago

Read 2 more answers

ASAP!

ANTONII [103]

Two figures are known as similar figures if there the corresponding angles are equal and the corresponding sider is in ratio. The value of x is 10. Thus, the correct option is B.

<h3>What are Similar Figures?</h3>

Two figures are known as similar figures if there the corresponding angles are equal and the corresponding sider is in ratio. It is denoted by the symbol "~".

Since the two prisms are similar, their sides will be in a common ratio. The value of the common ratio will be,

Common ratio = 4/2 = 5/2.5 = 3/1.5 = 2

Since the common ratio of every side is equal to 2, the value of x can be written as,

Common Ratio = 20/x = 2

20/x = 2

x = 10

Hence, the value of x is 10. Thus, the correct option is B.

Learn more about Similar Figures:

brainly.com/question/11315705

#SPJ1

3 0

2 years ago